compiler: fix RegexSet bug #369
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When compiling a RegexSet, it was possible for the jump locations to
become incorrect if the last regex in the set had a starting location
that didn't correspond to the beginning of its program. This can happen
in simple cases like when your set consists of the regexes `a` and `β`.
In particular, the program for `β` is:
0: Bytes(\xB2) (goto 2)
1: Bytes(\xCE) (goto 0)
2: MATCH
Where the entry point is `1` instead of `0`. To fix this, we compile a
set of regexes similarly to how we compile `a|β`, where we handle the
holes produced by sub-expressions correctly.
Fixes #353
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@bors r+ |
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📌 Commit cd8f6eb has been approved by |
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May 20, 2017
compiler: fix RegexSet bug
When compiling a RegexSet, it was possible for the jump locations to
become incorrect if the last regex in the set had a starting location
that didn't correspond to the beginning of its program. This can happen
in simple cases like when your set consists of the regexes `a` and `β`.
In particular, the program for `β` is:
0: Bytes(\xB2) (goto 2)
1: Bytes(\xCE) (goto 0)
2: MATCH
Where the entry point is `1` instead of `0`. To fix this, we compile a
set of regexes similarly to how we compile `a|β`, where we handle the
holes produced by sub-expressions correctly.
Fixes #353
|
☀️ Test successful - status-appveyor, status-travis |
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When compiling a RegexSet, it was possible for the jump locations to
become incorrect if the last regex in the set had a starting location
that didn't correspond to the beginning of its program. This can happen
in simple cases like when your set consists of the regexes
aandβ.In particular, the program for
βis:Where the entry point is
1instead of0. To fix this, we compile aset of regexes similarly to how we compile
a|β, where we handle theholes produced by sub-expressions correctly.
Fixes #353