Popup Control for ASP.NET Web Forms - How to show the loading panel when loading content

This example demonstrates how use the popup control's client-side functionality to display the loading panel in a pop-up window when content is loading slowly.

Overview

The main idea is to call the popup control's client-side GetContentIFrame method to get the control's IFrame. Then use the loading panel's ShowInElement method to display the panel within the IFrame. When content is loaded, hide the loading panel.

<dx:ASPxLoadingPanel ID="lp" runat="server" ClientInstanceName="lp" />
<dx:ASPxPopupControl ID="popup" runat="server" ... >
    <ClientSideEvents Init="OnPopupInit" Shown="OnPopupShown" />
</dx:ASPxPopupControl>

var showPopup = true;
var iframe;
function OnPopupInit (s, e) {
    iframe = popup.GetContentIFrame();
    ASPxClientUtils.AttachEventToElement(iframe, 'load', OnContentLoaded);
}

function OnPopupShown (s, e) {
    if(showPopup)
        lp.ShowInElement(iframe);
}
function OnContentLoaded (e) {
    showPopup = false;
    lp.Hide();
}

Files to Review

• Default.aspx (VB: Default.aspx)
• TestPage.aspx.cs (VB: TestPage.aspx.vb)

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